刷题笔记:parallel-comparator-200

前言

来源：school-ctf-winter-2015

这题目名字也忒长了，linux c题

题解

just_a_string = [115, 116, 114, 97, 110, 103, 101, 95,
                 115, 116, 114, 105, 110, 103, 95, 105, 116, 95, 105, 115]
differences = [0, 9, -9, -1, 13, -13, -4, -11, -
               9, -1, -7, 6, -13, 13, 3, 9, -13, -11, 6, -7]

for j in range(26):
    flag = ""
    for i in range(20):
        flag += chr(differences[i]+j+97)
    print(flag)

爆破，然后看哪个可能性大
爆破也分正反向啊