刷题笔记:[百越杯2018]crazy

前言

题解

v = '327a6c4304ad5938eaf0efb6cc3e53dc'

flag = ''

for i in range(32):
    flag += chr((ord(v[i])-11 ^ 0x13)-23 ^ 0x50)


print(flag)
#v2=flag ^ 0x50+23
# v4=v2^0x13+11